Since base twelve has divisors 2, 3, 4 and 6 no primes ending in 2, 3, 4, 6, 8, 9 or A12 will appear. This leaves 1, 5, 7, B12.
2: 2 3: 3 5: 5 7: 7 11: b 13: 11 17: 15 19: 17 23: 1b 29: 25 31: 27 37: 31 41: 35 43: 37 47: 3b 53: 45 59: 4b 61: 51 67: 57 71: 5b 73: 61 79: 67 83: 6b 89: 75 97: 81 101: 85 103: 87 107: 8b 109: 91 113: 95 127: a7 131: ab 137: b5 139: b7 149: 105 151: 107 157: 111 163: 117 167: 11b 173: 125 179: 12b 181: 131 191: 13b 193: 141